(Image credit: Pinterest) Math quizzes measure your problem-solving skills and help you estimate how well you understand a problem. One such interesting question is: “I am a 4-digit number between 5000 and 6000. My ones place is half the tens place. My hundreds place is 3 times the tens place. I What number is it?”
How to solve this?
Solving this equation requires simple calculations. The first digit of the number starts with 5 because the number is between 5000 and 6000. Now the job is to find the other digits of the 4-digit number. Put the digit in the tens place as x. Applying the estimate in the question, the digit in the hundreds place is 3x and the digit in the ones place is x/2.
Now, since x is double the units digit, it means even digits like 2, 4, 6, and 8.
Again, the digit in the hundreds place is three times the number in the tens place, meaning that the number is a multiple of 3. Judging by the choices, the only number that meets this criterion is 6. Therefore, the answer The correct answer is 5621. Understand this more” So the numbers are arranged as follows: thousands, hundreds, tens, units. Thousands 5 or 6, hun 3t, tens t, units (1/2)t0 cannot be calculated for the tens column because the number will have 0 digits in the last 3 positions, making 5000 or 6000 and it must be between the two tens digits because of the single digit units is half that digit so t=2 produces units as 1 and hundreds as 6so 5621 is a possibility. Let’s try t=4 which produces units as 2 and hundreds as 12, This doesn’t work. A larger t would produce an unacceptable value of hundreds. Our result is 5621,” explains Quora user. Another user explains this another way. digits are a,b,c and d . The given conditions are:6000>(1000a+100b+10c+d)>5000, so a=5 .Assume that each digit is one integer and has only a single digit, d must be 1 . If d is greater than 1 then b will be a two-digit number. This means:d=1 c=2 because c=2d b=6 because b=3c So you are 5621″
